There are speculations that actor Ranveer Singh is behind the negative PR of Akshaye Khanna.
Many fans expected his return in Drishyam 3. Recent gossip, however, suggests that the actor ceases to be a part of the franchise going forward.
Drishyam franchise producer Mangat Pathak, recently spoke about Akshaye Khanna exiting Drishyam 3. He also addressed the actor’s conduct amidst discussions. According to him, the team had formally approached Khanna for the role.
The producer claimed the makers agreed to Akshaye Khanna’s high fee after the success of Dhurandhar. Talks were nearly finalised. At that stage, Akshaye reportedly insisted on wearing a wig for the film.
Soon after making this demand, the actor allegedly chose to walk away from the project. The decision surprised the team. Losing such a key character has forced the makers to rethink their casting plans.
Reports suggest Jaideep Ahlawat has now been brought in as a replacement. The move has sparked debate around personal insecurities influencing career choices. Many feel talented actors sometimes step away from big projects for avoidable reasons.
In his early career, Akshaye Khanna faced heavy trolling over his hair. That history explains his insecurity to some extent. Over the years, he has repeatedly proven his range and remains one of the most underrated performers in the industry.
While he held his own in Dhurandhar, franchises like Drishyam offer him greater scope to shine. Letting go of such a role may not have been a wise call.
Adding another layer, some Ranbir Kapoor fans believe this controversy links to a larger PR narrative. They suspect Ranveer Singh is behind negative PR against Khanna. According to these fans, Khanna drew attention away from Ranveer in the film.
For now, attention remains on how Jaideep Ahlawat fits into Drishyam 3. Fans are divided over the casting change. Many are disappointed by the exit of a strong performer and concerned about fan wars overshadowing the work.
News Edit KV Raman
Is Ranveer Singh behind Akshaye’s Negative PR?
